LC / RLC Resonant Frequency Calculator
In an LC or RLC tank circuit, electrical resonance occurs at the natural frequency f₀ where inductive reactance X_L exactly cancels capacitive reactance X_C: f₀ = 1 / (2 × π × √(L × C)).
Natural LC oscillation frequency in Hertz
Inductance in millihenries (switch inline unit for μH or H)
Capacitance in microfarads (switch inline unit for nF or pF)
Step-by-Step Calculation
In an LC or RLC tank circuit, electrical resonance occurs at the natural frequency f₀ where inductive reactance X_L exactly cancels capacitive reactance X_C: f₀ = 1 / (2 × π × √(L × C)).
Real-World Reference Values
Resonant inductive power transfer standard
Tuned loop antenna with pF capacitor bank
Determines Q-factor alongside series resistance R
20-Row Comparison Table
Resonant Frequency (f₀) · Tank Inductance (L)
| # | Tank Inductance (mH) | Resonant Frequency (Hz) | Δ % |
|---|---|---|---|
| 01 | 0.5 mHCurrent | 7,117.63 Hz | 0.00% |
| 02 | 72.3948 mH | 591.5158 Hz | -91.69% |
| 03 | 144.7896 mH | 418.265 Hz | -94.12% |
| 04 | 217.1843 mH | 341.512 Hz | -95.20% |
| 05 | 289.579 mH | 295.7581 Hz | -95.84% |
| 06 | 361.9738 mH | 264.5341 Hz | -96.28% |
| 07 | 434.3685 mH | 241.4855 Hz | -96.61% |
| 08 | 506.7632 mH | 223.5721 Hz | -96.86% |
| 09 | 579.1579 mH | 209.1325 Hz | -97.06% |
| 10 | 651.5527 mH | 197.1721 Hz | -97.23% |
| 11 | 723.9474 mH | 187.0538 Hz | -97.37% |
| 12 | 796.3421 mH | 178.3488 Hz | -97.49% |
| 13 | 868.7369 mH | 170.756 Hz | -97.60% |
| 14 | 941.1316 mH | 164.0571 Hz | -97.70% |
| 15 | 1,013.53 mH | 158.0893 Hz | -97.78% |
| 16 | 1,085.92 mH | 152.7288 Hz | -97.85% |
| 17 | 1,158.32 mH | 147.879 Hz | -97.92% |
| 18 | 1,230.71 mH | 143.4637 Hz | -97.98% |
| 19 | 1,303.11 mH | 139.4217 Hz | -98.04% |
| 20 | 1,375.50 mH | 135.7031 Hz | -98.09% |
Frequently Asked Questions
How do I find the tuning capacitor C needed to resonate an antenna coil at 13.56 MHz?+
Click SOLVE FOR on C, switch f₀ unit to MHz and enter 13.56, and enter your coil inductance L in μH.
What is the total impedance of a series RLC circuit at resonance f₀?+
At f = f₀, X_L and X_C cancel completely, leaving pure resistive impedance Z = R and unity power factor (PF = 1.0).
How does doubling both L and C affect resonant frequency?+
Multiplying both L and C by 2 increases √(LC) by 2, cutting resonant frequency f₀ in half.