Ohm's Law Voltage, Current & Resistance Calculator
Ohm's Law states that the electrostatic potential difference V across an ideal conductor is directly proportional to the current I flowing through it and its electrical resistance R: V = I × R.
Electromotive potential across the load in Volts
Charge flow rate in Amperes
Conductor or load resistance in Ohms
Step-by-Step Calculation
Ohm's Law states that the electrostatic potential difference V across an ideal conductor is directly proportional to the current I flowing through it and its electrical resistance R: V = I × R.
Real-World Reference Values
Up to 5A (100W) or 48V 5A (240W EPR)
Lead-acid / LiFePO4 starter & accessory rail
Low quiescent digital bus termination
20-Row Comparison Table
Voltage (Potential Difference) (V) · Electric Current (I)
| # | Electric Current (A) | Voltage (Potential Difference) (V) | Δ % |
|---|---|---|---|
| 01 | 0.001 A | 0.024 V | -99.80% |
| 02 | 0.5 ACurrent | 12 V | 0.00% |
| 03 | 1.5009 A | 36.0211 V | +200.18% |
| 04 | 2.2508 A | 54.0197 V | +350.16% |
| 05 | 3.0008 A | 72.0183 V | +500.15% |
| 06 | 3.7507 A | 90.0168 V | +650.14% |
| 07 | 4.5006 A | 108.0154 V | +800.13% |
| 08 | 5.2506 A | 126.0139 V | +950.12% |
| 09 | 6.0005 A | 144.0125 V | +1100.10% |
| 10 | 6.7505 A | 162.0111 V | +1250.09% |
| 11 | 7.5004 A | 180.0096 V | +1400.08% |
| 12 | 8.2503 A | 198.0082 V | +1550.07% |
| 13 | 9.0003 A | 216.0068 V | +1700.06% |
| 14 | 9.7502 A | 234.0053 V | +1850.04% |
| 15 | 10.5002 A | 252.0039 V | +2000.03% |
| 16 | 11.2501 A | 270.0024 V | +2150.02% |
| 17 | 12 A | 288.001 V | +2300.01% |
| 18 | 12.75 A | 305.9996 V | +2450.00% |
| 19 | 13.4999 A | 323.9981 V | +2599.98% |
| 20 | 14.2499 A | 341.9967 V | +2749.97% |
Frequently Asked Questions
How do I use kΩ or mA in Ohm's Law without manual conversion?+
Use the inline unit dropdown next to I or R to select Milliamperes (mA) or Kilohms (kΩ). The engine converts to base SI Amperes and Ohms automatically.
Does Ohm's Law apply to AC circuits?+
Yes, when resistance R is generalized to complex impedance Z (V = I × Z) accounting for inductive and capacitive reactance.
How do I compute power dissipated in the resistor?+
Combine Ohm's Law with Joule heating: P = V × I = I² × R = V² / R.